-(1/9)r^2+36=0

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Solution for -(1/9)r^2+36=0 equation:



-(1/9)r^2+36=0
Domain of the equation: 9)r^2!=0
r!=0/1
r!=0
r∈R
We add all the numbers together, and all the variables
-(+1/9)r^2+36=0
We multiply all the terms by the denominator
-(+1+36*9)r^2=0
We add all the numbers together, and all the variables
-325r^2=0
a = -325; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-325)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$r=\frac{-b}{2a}=\frac{0}{-650}=0$

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